Assignment 7: Maximum of a profit function.

Assignment 7: Maximum of a profit function.

Based on the assignment, we got the:
TR=1400Q -7.5Q^2
TC=Q^3-6Q^2+140Q+750

Revenue= TR-TC
So, we can get the function of profit is :
Profit=1260Q-1.5Q^2-Q^3-750

MR=1400-15Q
MC=3Q^2-12Q+140

We can draw the graph of TR,TC,PROFIT ,MR and MC.

When MC=MR , the company achieve the most profit.

According to the graph of MC and MR, we can see that when Q=20, MC=MR.
When Q=20 the profit is biggest. Profit=15850